An alternating current with a peak value of 5A passes through a resistor of resistance...
PHYSICSWAEC 1997
An alternating current with a peak value of 5A passes through a resistor of resistance 10Ω. Calculate the rate at which energy is dissipated in the resistor
- A. 250W
- B. 125W
- C. 50W
- D. 35.4W
Correct Answer: A. 250W
Explanation
P=\(I^2R= 25\times 10=250W\)
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