A ball thrown vertically upward reaches a maximum height of 50 m above the level
PHYSICSWAEC 2001
A ball thrown vertically upward reaches a maximum height of 50 m above the level of projection. Calculate the;
(i) time taken to reach the maximum height,
(ii) speed of the throw. [g = 10 ms\(^{-2}\)]
Explanation
V\(_1\) = U - gt
U = V + gt = 0 + 10t
h = ut\(\frac{1}{2}\) - gt\(^2\),
50 = 10t\(^2\) \(\frac{1}{2}\) x 10 t\(^2\)
50 = 10t\(^2\) - 5t\(^2\)
50 = 5t\(^2\) = 10
t\(^2\) = 10
t = \(\sqrt{10}\) = 3.16s
(ii) V = U - gt, O = U - 10 x 3.16
U = 31.16
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly.
Your email address will not be published. Required fields are marked *