Simplify (8^{n} times 2^{2n} div 4^{3n})
FURTHER MATHEMATICSWAEC 2006
Simplify \(8^{n} \times 2^{2n} \div 4^{3n}\)
- A. \(2^{-n}\)
- B. \(2^{1 - n}\)
- C. \(2^{n}\)
- D. \(2^{n + 1}\)
Correct Answer: A. \(2^{-n}\)
Explanation
\(8^{n} \times 2^{2n} \div 4^{3n} = 2^{3n} \times 2^{2n} \div 2^{6n}\)
\(2^{2n + 3n - 6n}\)
= \(2^{-n}\)
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