Age(in years) 1 - 5 6 - 10 11 - 15 Frequency 3 5 2

FURTHER MATHEMATICSWAEC 2006
Age(in years)1 - 56 - 1011 - 15
Frequency352

Calculate the standard deviation of the distribution.

  • A. 1.10
  • B. 2.36
  • C. 3.50
  • D. 7.50

Correct Answer: C. 3.50

Explanation

Age

(years)

Freq

(f)

Mid-value

(x)

fx\(d = (x - \bar{x})\)\(d^{2}\)\(fd^{2}\)
1 - 5339- 4.520.2560.75
6 - 1058400.50.251.25
11 - 15213265.530.2560.5
\(\sum =\)1075122.5

\(Mean (\bar {x}) = \frac{\sum fx}{\sum f} = \frac{75}{10} = 7.5\)

\(SD = \sqrt{\frac{\sum fd^{2}}{\sum f}}\)

= \(\sqrt{\frac{122.5}{10}}\)

= \(\sqrt{12.25} = 3.50\)

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