An object is projected vertically upwards with a velocity of 80 m/s. Find the :

FURTHER MATHEMATICSWAEC 2006

An object is projected vertically upwards with a velocity of 80 m/s. Find the :

(a) Maximum height reached

(b) Time taken to return to the point of projection. [Take g = \(10 ms^{-2}\)].

Explanation

(a) Maximum height reached

Using the equation, \(v^{2} = u^{2} - 2gs\) (Upward movement against gravity)

velocity at maximum height = 0 m/s

\(0 = 80^{2} - 2(10)s\)

\(0 = 6400 - 20s \implies 6400 = 20s \)

\(s = 320 m\)

(b) Time to reach the maximum height

\(v = u + at = u - gt\)

\(0 = 80 - 10t \implies 80 = 10t\)

\(t = 8s\)

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