The table shows the frequency distribution of marks scored by some candidates in an examination....
FURTHER MATHEMATICSWAEC 2011
The table shows the frequency distribution of marks scored by some candidates in an examination.
| Marks | 0-9 | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 | 90-99 |
| Freq | 2 | 5 | 8 | 18 | 20 | 15 | 5 | 4 | 2 | 1 |
(a) Draw the cumulative frequency curve of the distribution.
(b) Use your graph to estimate the :
(i) semi-interquartile range of the distribution; (ii) percentage of candidates who passed with distinction if the least mark for distinction was 72.
Explanation
| Marks | Class boundaries | Freq | Cum Freq |
| 0-9 | 0 - 9.5 | 2 | 2 |
| 10 - 19 | 9.5 - 19.5 | 5 | 7 |
| 20 - 29 | 19.5 - 29.5 | 8 | 15 |
| 30 - 39 | 29.5 - 39.5 | 18 | 33 |
| 40 - 49 | 39.5 - 49.5 | 20 | 53 |
| 50 - 59 | 49.5 - 59.5 | 15 | 68 |
| 60 - 69 | 59.5 - 69.5 | 5 | 73 |
| 70 - 79 | 69.5 - 79.5 | 4 | 77 |
| 80 - 89 | 79.5 - 89.5 | 2 | 79 |
| 90 - 99 | 89.5 - 99.5 | 1 | 80 |
(a)
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(b)(i) Lower quartile, \(Q_{1} = 32.5\)
Upper quartile, \(Q_{3} = 53.0\)
Semi-interquartile range = \(\frac{1}{2} (Q_{3} - Q_{1})\)
= \(\frac{1}{2} (53.0 - 32.5) = \frac{1}{2} (20.5)\)
= \(10.25\)
(ii) Number of students that passed with distinction = (80 - 74)
= 6 students
Percentage = \(\frac{6}{80} \times 100% = 7.5%\)
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